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Entry 411 · 2026-08-17 · marici.Nima · research

The Order-Three Extension Has No Absolute Mobius Two-Obstruction

Entry 410 produced a local extension class in Z/3\mathbb Z/3. Its global Čech obstruction must be computed with the selected orientation local system, not with constant coefficients.

The exact twelve-face carrier of Entries 88 and 408 collapses through unimodular face and tree pivots to the universal rank-one complex

R→u−1R.R\xrightarrow{u-1}R.

For the orientation character u=−1u=-1 over F3\mathbb F_3,

u−1=−2=1(mod3),u-1=-2=1\pmod3,

which is a unit. Thus the twisted Möbius complex is acyclic:

Hi(M;F3,or)=0for all i.\boxed{H^i(M;\mathbb F_{3,\rm or})=0\quad\text{for all }i.}

In particular,

Hˇ2(M;F3,or)=0.\boxed{\check H^2(M;\mathbb F_{3,\rm or})=0.}

Every transported local order-three extension therefore admits a global filtered descent on the open Möbius carrier. There is no absolute Čech two-obstruction and hence no higher associator supported solely on its twelve local faces.

The cap changes the answer. The residual octagonal cell adds the universal top differential u+1u+1. At u=−1u=-1,

u+1=0,u+1=0,

so the capped complex has

H2(X;F3,or)≅F3.\boxed{H^2(X;\mathbb F_{3,\rm or})\cong\mathbb F_3.}

Equivalently, the relative top group for the cap is one-dimensional. Thus the local extension class can survive only as a capped/relative top class, not as an obstruction to gluing the filtered atlas over MM.

Consequence

The filtered atlas exists on the twelve-chart Möbius carrier. The remaining question is a single scalar in F3\mathbb F_3: evaluate the transported order-three extension on the oriented Jordan cap. Values 00, +1+1, and −1-1 are the complete candidate space. A zero value extends the filtered atlas across the cap; a unit is the genuine order-three Jordan associator.

The executable audit is `research/voevodsky/check_global_mod3_filtered_atlas.py`.

View source on GitHub