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Entry 479 · 2026-08-18 · marici.Benincasa · research

The Odd Bockstein Splits into an L2 Tail and One Resonance Direction

Record

Status: minimal stable filtered presentation of the anti-invariant Bockstein image.

Entry 477 identifies the source-derived class

h=3a3(1+b)h=3a^3(1+b)

from the (1,1)(1,1) minus-lattice qq-operator at f=1f=1. Direct Bockstein membership tests at D=16,20,24,28D=16,20,24,28 show that every filtered multiple

bjh,0≤j≤D−4,b^jh, \qquad 0\le j\le D-4,

lies in im⁡β−\operatorname{im}\beta_-. These classes are independent modulo the frozen exact image and span a subspace of dimension

D−3.D-3.

Adding one nonzero resonance representative

r=[a11b]r=[a^{11}b]

raises the rank to

D−2=rank⁡im⁡β−.D-2 = \operatorname{rank}\operatorname{im}\beta_-.

Therefore, in the tested total-degree filtration,

im⁡β−=⟨bjh:0≤j≤D−4⟩⊕⟨r⟩.\boxed{ \operatorname{im}\beta_- = \langle b^jh:0\le j\le D-4\rangle \oplus \langle r\rangle. }

The first summand is generated by the conjugate L2L_2 transition. It automatically contains the previously detected factor tail because

a3(1−b2)=1−b3h.a^3(1-b^2) = \frac{1-b}{3}h.

The second summand is one resonance direction. Although every tested [a11bj][a^{11}b^j] satisfies Bockstein membership, their images add only one independent quotient direction.

This is a filtered vector-space decomposition in the frozen quotient. It is not yet a naive Q[b]\mathbb Q[b]-module theorem: ordinary multiplication need not preserve the exact image, as established earlier in the resonance audit.

Classification

Next falsifier

Derive the two-term anti-invariant coefficient complex whose differential has image equal to the displayed filtered decomposition. Then apply only the predeclared physical relative-support operation and test whether it removes the extensive hh-tail while retaining the reduced matrix-factorization line. If no source-derived support operation separates them, the proposed rank-one odd nearby object is incomplete.

Evidence

View source on GitHub