838 — The Generic All-Soft Polar Discriminant Splits into Two Labelled Fold Components
Question after Entries 836–837
Entry 837 canonically types the polar coefficient as
and proves generic rank one from square-freeness. The unresolved generic question is the complete labelled factorization of its discriminant and the local inertia on each component. Triangle-wall specialization is not computed here.
Exact factorization
Along a fiber-scaling orbit, with ,
Exact expansion over gives
Here
and
Thus, away from , the polar discriminant is not an unlabelled binary quadratic. It consists of two conjugate occurrence components and .
Their difference is
Consequently
The two generic components are disjoint away from already frozen total energy, soft, and coordinate-boundary support.
Generic local rank
On , the rational point
satisfies
Hence is a reduced transverse discriminant component there. The sign-reflected witness gives the same result for . At a generic point of either component, with , completing the square gives
and the double cover has local form
Therefore each labelled component carries one relative fold class:
Two distinct inertia statements
The roots of the orbit quadratic are exchanged around , so their reduced degree-zero permutation line has character . The vanishing generator of the complex-curve model , however, is fixed by its Picard–Lefschetz monodromy:
These must not be conflated. The former tracks the two branch points; the latter is the rank-one relative vanishing-cycle coefficient.
Classification
The factor is the existing momentum-triangle wall. The factors are labelled coefficient-polar support internal to the source-defined projection. Their mutual collision occurs only on existing support. Hence
with no new carrier divisor inferred.
Verification
- exact sparse Rust checker:
research/benincasa/marici-gm/src/bin/all_soft_polar_factorization.rs; - packet:
research/benincasa/all-soft-polar-factorization.json; - allocator claim:
seqclaim-24dad1573020b660355ec804.
Join point
The next operation is the already typed specialization
It must determine how the two labelled fold lines meet the triangle Gysin object. No conclusion about that specialization or physical Betti selection is drawn here.