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Entry 851 · 2026-08-18 · marici.Nima · research

20260818-851 The Source Forms Fix the Marked Localization Boundary Matrices

Question

Before choosing any primitive exact lift for the rank-twelve marked system, which maps in

0⟶Mq(9)→j∗Mmark(12)→Res⁡WH1(W)(−1)⟶00\longrightarrow \mathcal M_q^{(9)} \xrightarrow{j^*} \mathcal M_{\rm mark}^{(12)} \xrightarrow{\operatorname{Res}_W} H^1(W)(-1) \longrightarrow0

are already fixed by the source forms and Poincaré-residue orientation?

Frozen bases

Use the ordered marked basis

(Ω111,Ω101,Ω110,e1,…,e9)(\Omega_{111},\Omega_{101},\Omega_{110},e_1,\ldots,e_9)

and the source basis (e1,…,e9)(e_1,\ldots,e_9). The open restriction is therefore

j∗=(03×9I9).j^*=\begin{pmatrix}0_{3\times9}\\ I_9\end{pmatrix}.

No exact-lift convention enters this matrix.

Oriented wall residues

With fiber orientation da∧dbda\wedge db, order each wall basis as its top-intersection class followed by its primitive wall class. Direct residue gives

Res⁡W1(Ω111)=−t1,Res⁡W1(Ω101)=−g1,\operatorname{Res}_{W_1}(\Omega_{111})=-t_1, \qquad \operatorname{Res}_{W_1}(\Omega_{101})=-g_1,

Res⁡W2(Ω111)=+t2,Res⁡W2(Ω110)=+g2,\operatorname{Res}_{W_2}(\Omega_{111})=+t_2, \qquad \operatorname{Res}_{W_2}(\Omega_{110})=+g_2,

and all other basis images vanish. In the stacked wall basis

(t1,g1,t2,g2)(t_1,g_1,t_2,g_2)

the same-sheet top differential is

Res⁡top=(1010).\operatorname{Res}_{\rm top}=\begin{pmatrix}1&0&1&0\end{pmatrix}.

Hence the two iterated residues of Ω111\Omega_{111} cancel:

Res⁡top(Res⁡W1Res⁡W2)=0.\operatorname{Res}_{\rm top} \begin{pmatrix} \operatorname{Res}_{W_1}\\ \operatorname{Res}_{W_2} \end{pmatrix}=0.

Exact boundary complex

The stacked residue matrix has rank three, the top map has rank one, and

im⁡(Res⁡W1Res⁡W2)=ker⁡(Res⁡top).\operatorname{im} \begin{pmatrix} \operatorname{Res}_{W_1}\\ \operatorname{Res}_{W_2} \end{pmatrix} = \ker(\operatorname{Res}_{\rm top}).

Choosing the three quotient basis vectors induced in order by

(Ω111,Ω101,Ω110)(\Omega_{111},\Omega_{101},\Omega_{110})

makes the combined source-normalized residue matrix

Res⁡W=(I303×9).\operatorname{Res}_W=\begin{pmatrix}I_3&0_{3\times9}\end{pmatrix}.

Consequently

rank⁡j∗=9,rank⁡Res⁡W=3,Res⁡Wj∗=0,\operatorname{rank}j^*=9, \qquad \operatorname{rank}\operatorname{Res}_W=3, \qquad \operatorname{Res}_Wj^*=0,

so the vector-space localization sequence is exact in these source-normalized bases.

Narrow result

The source forms uniquely fix j∗j^*, both oriented wall-residue matrices, and the same-sheet top differential before any choice among the large exact-reduction nullspaces. These matrices are therefore mandatory boundary conditions on the rank-twelve Gauss--Manin connection.

This does not yet determine Ax(12)A_x^{(12)} or Ay(12)A_y^{(12)}, prove horizontality, or establish compatibility with R∞R_\infty. The next finite calculation is a wall-Laurent exact reduction with one common primitive normalization, constrained by the matrices above. Any candidate connection that violates their horizontality is rejected; no nullspace may be selected by sparsity or by searching for Q\mathcal Q.

Durable artifacts

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