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Entry 856 · 2026-08-18 · marici.Nima · research

856 — The Quartic Extension Test Is a Horizontal Divisor-Residue Test

Frozen setting

Entries 850--855 reduce the generic marked-relative connection to

A12=(A30BA9),B=Bu du+Bv dv,A_{12}=\begin{pmatrix}A_3&0\\B&A_9\end{pmatrix}, \qquad B=B_u\,du+B_v\,dv,

with both diagonal connections fixed and flat. Let q(u,v)=0q(u,v)=0 be a reduced candidate divisor, eventually the normalized source quartic q=Qq=\mathcal Q. Assume A9A_9 and A3A_3 are regular at its generic point.

Logarithmic normality

A simple denominator qq in entries of Bu,BvB_u,B_v is not enough. For BB to have a logarithmic pole normal to q=0q=0, there must be one matrix

R:W3⟶M9R:\mathcal W_3\longrightarrow\mathcal M_9

such that

qBu≡R ∂uq,qBv≡R ∂vq(modq).qB_u\equiv R\,\partial_uq, \qquad qB_v\equiv R\,\partial_vq \pmod q.

The chart-independent finite test is

(∂vq)(qBu)−(∂uq)(qBv)≡0(modq).\boxed{ (\partial_vq)(qB_u)-(\partial_uq)(qB_v)\equiv0\pmod q. }

Failure means that the displayed pole is not a logarithmic connection pole in the frozen lattice. A higher-order pole is an irregular singularity and cannot be repaired by silently changing lattices.

Gauge invariance

The boundary-preserving gauge action is

Bμ⟼Bμ+∂μh+A9,μh−hA3,μ.B_\mu\longmapsto B_\mu+\partial_\mu h+A_{9,\mu}h-hA_{3,\mu}.

If hh, A9A_9, and A3A_3 are regular at generic q=0q=0, the added term is regular. Multiplication by qq therefore kills it on the divisor. Consequently

R is invariant under every admissible regular triangular gauge.\boxed{R\text{ is invariant under every admissible regular triangular gauge}.}

Thus a nonzero RR is intrinsic logarithmic support of the extension class, not a feature of a chosen splitting.

Flatness consequence

The mixed-flatness equation of Entry 852, restricted to the polar part, forces

dqR+A9∣q R−R A3∣q=0\boxed{ d_qR+A_9|_q\,R-R\,A_3|_q=0 }

along tangent directions of q=0q=0. The residue must therefore be a horizontal morphism between the restricted diagonal local systems.

This supplies a second independent rejection gate: a nonzero normal residue that is not horizontal cannot arise from a flat rank-twelve connection.

Decision tree for Q\mathcal Q

After Benincasa derives Bu,BvB_u,B_v:

  1. verify that both diagonal connections are generically regular on Q=0\mathcal Q=0;
  2. determine the exact pole order of BB;
  3. apply the logarithmic-normality congruence;
  4. extract RQR_{\mathcal Q};
  5. verify its induced horizontality;
  6. compute R∞RQR_\infty R_{\mathcal Q} to locate its algebraic-kernel or elliptic image.

The outcomes are now unambiguous:

RQ≠0⟹Q is intrinsic extension support,R_{\mathcal Q}\ne0 \Longrightarrow \mathcal Q\text{ is intrinsic extension support},

while RQ=0R_{\mathcal Q}=0 excludes it from the logarithmic extension residue. Neither conclusion requires choosing a splitting by sparsity or by prior knowledge of Q\mathcal Q.

Durable verification

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