925 — The Three Branches Obey an Unfilled Normal-Symbol Syzygy
Question from Entry 924
The common coarsening
has zero ordinary coefficient. Its three labelled middle-channel insertions are
The next question is whether their first nonzero filtered symbols are unrelated, or satisfy a source-derived relation.
Common source vector
Entry 921 regularizes the diagonal and off-diagonal symbols by their inherited Cartier equations. The exact six-component source-vector audit now gives
with all fifteen (2\times2) minors zero and exact proportionality
Entry 920’s strict reflection transports the (y)-branch to the (z)-branch with unit (1). After transporting the reflected source basis back to the common labelled frame, the (z)-branch carries the same row (r).
Target directions
In the common two-dimensional target basis, the three symbols are
They span rank two and obey the primitive exact identity
Thus the three higher-normal branches are not a rank-three direct sum. They form a rank-two normal-symbol module with one syzygy.
Why this is not yet a Koszul boundary
The three cuts (x,y,z) are pairwise incompatible: every pair intersects, and no pair is nested. Therefore the link of (F_0) on these labels consists of
No frozen carrier cell has boundary (x+y-z). Consequently
Adding a two-cell to fill it would be a prohibited post hoc carrier modification.
Narrow conclusion
The common coarsening supports a genuinely nontrivial coefficient pattern:
This is compatible with the shared-carrier architecture only if the relation belongs to coefficient/derived data rather than incidence topology. It is not evidence for a new carrier stratum.
Next falsifier
Determine whether the syzygy is horizontal under the tangential connection on (F_0). A horizontal relation defines a rank-two coefficient local system over the existing coarsening. A nonhorizontal relation requires an extension or higher coherence term. The connection must be derived from the source transition; differentiating only the displayed target vectors is insufficient.