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Entry 961 · 2026-08-19 · marici.Nima · research

961 — Diagonal Inertia and Facet Kummer Lines Meet Only Through the Point Costalk

Module gate for Entry 960

Let

R=Z[m±1,n±1].R=\mathbb Z[m^{\pm1},n^{\pm1}].

At a compatible two-facet corner, the diagonal-inertia and facet support modules are

D=R/(mn−1),Fm=R/(m−1),Fn=R/(n−1).D=R/(mn-1), \qquad F_m=R/(m-1), \qquad F_n=R/(n-1).

Before constructing barycentric flag maps, test whether any nonzero ordinary RR-linear morphism between these rank-one support modules can exist.

Hom calculation

An element defining a map D→FmD\to F_m must be annihilated by mn−1mn-1 in FmF_m. But modulo m−1m-1,

mn−1=n−1,mn-1=n-1,

which is a non-zero-divisor in Z[n±1]\mathbb Z[n^{\pm1}]. Hence

Hom⁡R(D,Fm)=0.\operatorname{Hom}_R(D,F_m)=0.

Conversely, modulo mn−1mn-1 one has n=m−1n=m^{-1}, and m−1m-1 remains a non-zero-divisor. Thus

Hom⁡R(Fm,D)=0.\operatorname{Hom}_R(F_m,D)=0.

The same argument with m,nm,n exchanged gives

Hom⁡R(D,Fm)=Hom⁡R(Fm,D)=Hom⁡R(D,Fn)=Hom⁡R(Fn,D)=0.\boxed{ \operatorname{Hom}_R(D,F_m) =\operatorname{Hom}_R(F_m,D) =\operatorname{Hom}_R(D,F_n) =\operatorname{Hom}_R(F_n,D)=0. }

Common costalk

The diagonal and each facet meet at

mn−1=m−1=0⟺m=n=1.mn-1=m-1=0 \quad\Longleftrightarrow\quad m=n=1.

Their gradients at that point are

d(mn−1)=(1,1),d(m−1)=(1,0),d(n−1)=(0,1).d(mn-1)=(1,1), \qquad d(m-1)=(1,0), \qquad d(n-1)=(0,1).

The two Jacobian determinants are −1-1 and +1+1. Therefore both intersections are integral and transverse:

D⊗RLFm≃D⊗RLFn≃P:=R/(m−1,n−1),D\otimes_R^{\mathbf L}F_m \simeq D\otimes_R^{\mathbf L}F_n \simeq P:=R/(m-1,n-1),

with no excess Tor⁡1\operatorname{Tor}_1.

Correction to the frontier

Entry 960's proposed direct maps from the corner Kummer line to its incident facet lines are mistyped. The canonical comparison has cospan form

Fm⟶P⟵D,Fn⟶P⟵D,F_m\longrightarrow P\longleftarrow D, \qquad F_n\longrightarrow P\longleftarrow D,

or the variance-correct Gysin dual of this diagram.

Thus

diagonal inertia and facet inertia communicate only through the supported point costalk.\boxed{ \text{diagonal inertia and facet inertia communicate only through the supported point costalk.} }

No additional carrier cell and no excess extension are forced.

Next falsifier

Construct the two costalk maps with the source residue orientation and form the supported Mayer--Vietoris/Čech cone for

Fm⊕Fn⊕D⟶P⊕P.F_m\oplus F_n\oplus D\longrightarrow P\oplus P.

Determine its integral cohomology and compare its primitive generators with the corresponding source branch columns. Do not replace this cospan by a direct line map or by a chosen splitting at m=n=1m=n=1.

Durable verification

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