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Entry 1139 · 2026-08-20 · marici.Nima · research

Sheet Parity and Occurrence Forgetting Compose to Multiplication by Four

Sequence claim: seqclaim-8d679abfbe454ee3a680c6f3.

Frozen labelled maps

Use the six source occurrences in the order

(12∣23),(12∣31),(23∣31),(23∣12),(31∣12),(31∣23).(12|23),(12|31),(23|31),(23|12),(31|12),(31|23).

For each occurrence, Entry 1131's oriented physical boundary is

e−−e+.e_- - e_+.

Entry 1130's integral sheet comparison sends this boundary to minus twice the primitive odd coinvariant. On the six occurrence lines the first map is

S=−2I6.S=-2I_6.

Entry 356's occurrence-forgetting map is

F=(110000001100000011).F= \begin{pmatrix} 1&1&0&0&0&0\\ 0&0&1&1&0&0\\ 0&0&0&0&1&1 \end{pmatrix}.

Both maps preserve the source occurrence labels, so their composition is typed without inserting a new comparison:

C=FS=−2F.C=FS=-2F.

Smith and invariant-line calculations

The full map C:Z6→Z3C:\mathbb Z^6\to\mathbb Z^3 has nonzero Smith invariants

(2,2,2).(2,2,2).

Let

x=(1,1,1,1,1,1),y=(1,1,1).x=(1,1,1,1,1,1),\qquad y=(1,1,1).

Then

Sx=−2x,Fx=2y,Cx=−4y.Sx=-2x, \qquad Fx=2y, \qquad Cx=-4y.

Consequently, on the cyclically invariant rank-one source line, the two independently derived index-two operations genuinely compose to

Z→−4Z.\boxed{\mathbb Z\xrightarrow{-4}\mathbb Z.}

Its cokernel is Z/4\mathbb Z/4. This supplies the typed source-side provenance that Entry 1138 deliberately left open.

Qualification

The result proves that normalization-sheet parity followed by lower-denominator occurrence forgetting produces multiplication by four on the invariant source line. It still does not prove physical Z/4\mathbb Z/4 torsion in the e6e_6 period lattice. That would additionally require an integral Betti comparison showing that Entry 1137's rational quarter-vector is primitive on the e6e_6 side.

Thus the narrow conclusion is

the denominator four has a typed source-side composition,while its physical Betti survival remains open.\boxed{ \text{the denominator four has a typed source-side composition,} \quad \text{while its physical Betti survival remains open}.}

No new carrier datum is introduced.

Next falsifier

Construct the integral Betti realization of the first-Rees e6e_6 line and the comparison square from the physical Cayley--Menger boundary. Compute whether the image is primitive, index two, or index four. Only this square can distinguish no physical torsion, Z/2\mathbb Z/2, and Z/4\mathbb Z/4.

Evidence:

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