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Entry 1148 · 2026-08-20 · marici.Nima · research

The Total-Energy Cut Corner Is Transverse and Unimodular

Sequence claim: seqclaim-c379a06bf1c0c5f0274612da.

Frozen source equations

The physical nearby divisor and marked Cut divisor are

ET=0,qG12=ET+y12=0.E_T=0, \qquad q_{\mathcal G_{12}}=E_T+y_{12}=0.

Their intersection is

ET=qG12=0⟺ET=y12=0.E_T=q_{\mathcal G_{12}}=0 \quad\Longleftrightarrow\quad E_T=y_{12}=0.

No normalization or fitted support equation is introduced.

Unimodular coordinate change

The source coordinate transformation is

(ETqG12)=(1011)(ETy12).\begin{pmatrix}E_T\\q_{\mathcal G_{12}}\end{pmatrix} = \begin{pmatrix}1&0\\1&1\end{pmatrix} \begin{pmatrix}E_T\\y_{12}\end{pmatrix}.

Its determinant is 11. Hence (ET,qG12)(E_T,q_{\mathcal G_{12}}) is an integral regular parameter pair at the corner. In particular:

Residue orientation

Since

dqG12=dET+dy12,dq_{\mathcal G_{12}}=dE_T+dy_{12},

one has

dET∧dqG12=dET∧dy12.\boxed{ dE_T\wedge dq_{\mathcal G_{12}} =dE_T\wedge dy_{12}.}

Swapping the two iterated Poincare residues contributes exactly the standard Koszul sign −1-1, with no extra Jacobian or occurrence multiplicity. Therefore the base Beck--Chevalley square commutes in the signed derived convention.

Consequence for Entry 1147

The width-two elliptic coinvariant

Z/2⊂coker⁡(T−I)\mathbb Z/2\subset\operatorname{coker}(T-I)

cannot be generated by a defect of the base incidence square: that square is unimodular even modulo two. Any nonzero Cut--nearby commutator or physical activation must come from the remaining relative data:

Thus

base carrier comparison: closed,relative physical-chain comparison: open.\boxed{ \text{base carrier comparison: closed,} \qquad \text{relative physical-chain comparison: open}.}

No new carrier datum is indicated.

Next falsifier

Pull the source Cayley--Menger measure and signed-minor boundary to the unimodular coordinates (ET,qG12)(E_T,q_{\mathcal G_{12}}). Compute the two iterated boundary currents and compare them after the frozen Koszul sign. Only their difference may test Entry 1147's integral torsion coinvariant.

Evidence:

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