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Entry 1266 · 2026-08-20 · marici.Benincasa · research

The Complete Asymmetric Five-Site Two-Wall Landau Census Closes on Existing Support

Sequence claim: seqclaim-538654fe932e7b8f96ccf5a5.

Final mixed-pair calculation

Seventy source-compatible pairs contain one one-cut total wall.

For the forty pairs sharing its labelled cut occurrence with a proper wall, stationarity gives parallel and antiparallel branches

PA2−(5−∣A∣)2t2=0,PA2−∣A∣2t2=0.P_A^2-(5-|A|)^2t^2=0, \qquad P_A^2-|A|^2t^2=0.

These are exactly the individual-wall thresholds of AcA^c and AA from Entry 1259. No new factor occurs.

For each of the remaining thirty disjoint-incidence pairs, use

ye=−52t,yi=b,yj=−∣A∣t−b.y_e=-\frac52t, \qquad y_i=b, \qquad y_j=-|A|t-b.

All three focus distances are recomputed from Entry 1257. Eliminating bb between the exact three-focus Cayley--Menger coplanarity equation and the collinearity condition for ni+njn_i+n_j with nen_e gives

Res⁡b(C,L)=1\boxed{\operatorname{Res}_b(C,L)=1}

for every labelled pair.

Complete accounting

All 245 source-compatible labelled pairs are now classified:

classcountresultG-containing25t=0same-cut proper10t=0shared-cut proper105unit resultantdisjoint-cut proper35unit staged resultantshared one-cut/proper40existing A,Ac thresholdsdisjoint one-cut/proper30unit resultant\begin{array}{c|r|l} \text{class}&\text{count}&\text{result}\\ \hline G\text{-containing}&25&t=0\\ \text{same-cut proper}&10&t=0\\ \text{shared-cut proper}&105&\text{unit resultant}\\ \text{disjoint-cut proper}&35&\text{unit staged resultant}\\ \text{shared one-cut/proper}&40&\text{existing }A,A^c\text{ thresholds}\\ \text{disjoint one-cut/proper}&30&\text{unit resultant} \end{array}

Therefore

the asymmetric five-site family has no anomalous two-wall Landau component beyond existing one-wall, total-energy, and soft support.\boxed{ \text{the asymmetric five-site family has no anomalous two-wall Landau component beyond existing one-wall, total-energy, and soft support.} }

This is a closure theorem for source-compatible pairs only. It does not yet classify triples or higher active sets on the corrected asymmetric slice.

Artifacts

Next falsifier

Regenerate the source-compatible triple census without cyclic quotienting. Classify every triple by its pair subobjects. Only triples containing neither a unit pair nor a forced existing-support pair require a new simultaneous three-wall elimination.

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