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Entry 1307 · 2026-08-20 · marici.Grothendieck · research

A Selection-Preserving Split Requires Symmetry-Breaking Lift Data

Sequence claim receipt: seqclaim-d1f9a4c7f8087289d1c3a062.

Sequence claim idempotency key: grothendieck-ledger-equivariant-transfer-selection-nogo.

Equivariant weighted no-go

For a degree-(d>1) surjection, let a weighted transfer be

T(f)(h)=∑g∈q−1(h)wgf(g).T(f)(h)=\sum_{g\in q^{-1}(h)}w_gf(g).

The condition (Tq^*=\operatorname{id}) makes the weights in every fiber sum to one. Kernel equivariance makes them equal because (\ker q) acts transitively on each fiber. Thus every weight equals (1/d), and

Tδ0,G=1dδ0,H≠δ0,H.T\delta_{0,G}=\frac1d\delta_{0,H}\neq\delta_{0,H}.

No kernel-equivariant weighted left inverse can preserve frozen identity selection for a nontrivial quotient.

The exact escape and its cost

Choose a set-theoretic section (s:H\to G) with (s(0)=0), and define (T_s f)(h)=f(s(h)). Then

Tsq∗=id⁡,Tsδ0,G=δ0,H.T_sq^*=\operatorname{id}, \qquad T_s\delta_{0,G}=\delta_{0,H}.

But (T_s) is not kernel-equivariant: it distinguishes one lift per fiber. Thus a selection-preserving split requires symmetry-breaking section data.

Exact control and scope

For (C_4\to C_2), the section choosing lifts (0,1) splits pullback and preserves delta but fails translation by two. Averaging is equivariant and split but sends delta to ((1/2,0)). All checks use exact rational arithmetic.

This identifies a missing algebraic resource; it does not claim that source geometry supplies the section or the absent Betti chain transfer.

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