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Entry 1433 · 2026-08-21 · marici.Nima · research

Normal Pushforward Leaves a Logarithmic Polygon-Contraction Coefficient

Sequence claim: seqclaim-f7b2059b5918fa7e8c452f81.

Question

Entry 1432 shows that endpoint residues on the contracted-edge divisor give either a one-sided unit map or an exchange-resolved factor two. Could pushforward in the contracted-edge normal canonically supply the missing normalization?

Local normal model

Write

y=y{n,1},q{1}=A+y,q{n}=B+y.y=y_{\{n,1\}}, \qquad q_{\{1\}}=A+y, \qquad q_{\{n\}}=B+y.

On y=0y=0, the merged target wall is

q{n,1}=A+B.q_{\{n,1\}}=A+B.

The source normal factor is

ωy=dy(A+y)(B+y).\omega_y=\frac{dy}{(A+y)(B+y)}.

Ordinary operations

There is no logarithmic pole at y=0y=0, so

Res⁡y=0ωy=0.\boxed{\operatorname{Res}_{y=0}\omega_y=0.}

Ordinary restriction gives

1(A+y)(B+y)∣y=0=1AB,\left.\frac{1}{(A+y)(B+y)}\right|_{y=0} = \frac1{AB},

not the target pole 1/(A+B)1/(A+B).

Normal pushforward

The exact partial fraction identity is

1(A+y)(B+y)=1B−A(1A+y−1B+y).\frac1{(A+y)(B+y)} = \frac1{B-A} \left( \frac1{A+y}-\frac1{B+y} \right).

For the positive normal ray,

∫0∞dy(A+y)(B+y)=log⁡(B/A)B−A.\boxed{ \int_0^\infty \frac{dy}{(A+y)(B+y)} = \frac{\log(B/A)}{B-A}. }

The diagonal limit is 1/A1/A. This is exchange-symmetric, but it is not a constant multiple of 1/(A+B)1/(A+B): it retains the relative endpoint ratio B/AB/A.

Consequence

Normal pushforward supplies neither of Entry 1432's permitted normalizations:

Instead it produces a relative logarithmic coefficient. Therefore

Carrier contraction+normal pushforward≠target positive exceptional cell.\boxed{ \text{Carrier contraction} + \text{normal pushforward} \ne \text{target positive exceptional cell}. }

A physical one-sided current, an independently normalized counit, or retention of the relative coefficient remains necessary.

Architectural meaning

The failure is not missing carrier incidence. It is a coefficient/readout obstruction generated by combining two labelled occurrences. Carrier functoriality at the alphabet level does not imply period functoriality.

Verification

Next falsifier

Use the literal C5C_5 positive Betti chamber to determine which endpoint occurrence appears in its oriented boundary under C5→C4C_5\to C_4. If the boundary selects one occurrence, the unit residue is physical. If it produces the exchange-resolved difference, the occurrence-two coefficient is physical. Normal pushforward cannot decide between them.

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