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Entry 1528 · 2026-08-21 · marici.Nima · research

1528 — The Omitted Finite-Time Grades Have a Five-Equation Boundary-Closure Falsifier

Hard-to-vary claim

At first order in the quadratic initial action of arXiv:1408.4801, the real kernels Re⁡Ap\operatorname{Re}A_p, Im⁡Ap\operatorname{Im}A_p, and BpB_p span only a rank-three subspace of the rank-eight late-time trigonometric coefficient space. Therefore each omitted η0\eta_0-grade must satisfy five exact linear identities if the published quadratic coefficient object is sufficient.

Frozen basis

Let θ=2p(η−η0)\theta=2p(\eta-\eta_0), and order coefficients by

(cos⁡θ,ηcos⁡θ,η2cos⁡θ,sin⁡θ,ηsin⁡θ,η2sin⁡θ,1,η2).(\cos\theta,\eta\cos\theta,\eta^2\cos\theta, \sin\theta,\eta\sin\theta,\eta^2\sin\theta,1,\eta^2).

Equation (21) gives the three response directions

rRe⁡A=(0,−2p,0,1,0,−p2,0,0),r_{\operatorname{Re}A}=(0,-2p,0,1,0,-p^2,0,0),

rIm⁡A=(1,0,−p2,0,2p,0,0,0),r_{\operatorname{Im}A}=(1,0,-p^2,0,2p,0,0,0),

rB=(0,0,0,0,0,0,1,p2).r_B=(0,0,0,0,0,0,1,p^2).

They have generic rank three.

Exact annihilators

Writing a candidate loop grade as coefficients c∙c_\bullet, membership in the response span requires

cηcos⁡+2pcsin⁡=0,p2csin⁡+cη2sin⁡=0,c_{\eta\cos}+2p c_{\sin}=0, \qquad p^2c_{\sin}+c_{\eta^2\sin}=0,

p2ccos⁡+cη2cos⁡=0,−2pccos⁡+cηsin⁡=0,p^2c_{\cos}+c_{\eta^2\cos}=0, \qquad -2pc_{\cos}+c_{\eta\sin}=0,

−p2c1+cη2=0.-p^2c_{1}+c_{\eta^2}=0.

The Symbolica checker verifies exactly that all five functionals annihilate all three source response directions. As an end-to-end control, it also projects the printed Eq. (19) vector and obtains

(Re⁡A,Im⁡A,B)=(0,L,−J0),(\operatorname{Re}A,\operatorname{Im}A,B)=(0,L,-J_0),

where

L=J1−2J0−4J2−32c3(3ϵ+2δ)2.L=J_1-2J_0-4J_2- \frac{32c_3}{(3\epsilon+2\delta)^2}.

All five obstruction functionals vanish on this control.

Deutsch--Popperian decision rule

Artifacts

Verification

cargo run --release --bin finite_time_quadratic_response_span
exit code: 0
response rank: 3
annihilator rank: 5

Next falsifier

Contract Eq. (18), project its η01\eta_0^1 coefficient onto these five annihilators before evaluating the loop momentum integrals, and stop at the first nonzero obstruction. Only if that grade closes should the η00\eta_0^0 grade and subsequent Hadamard audit be computed.

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