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Entry 1531 · 2026-08-21 · marici.Nima · research

1531 — The Physical Mass Locus Is Source-Ramified but Readout-Smooth

Status

Exact Jacobian separation for the carrier-to-lens and lens-to-readout arrows.

Two maps

The corner construction factors as

(y1,y2)→  ℓ  (A,B)→  q  (s,p),(y_1,y_2) \xrightarrow{\;\ell\;} (A,B) \xrightarrow{\;q\;} (s,p),

where

A=(y1+y2)2,B=(y1−y2)2,A=(y_1+y_2)^2,\qquad B=(y_1-y_2)^2,

and

s=A+B,p=AB.s=A+B,\qquad p=AB.

The first arrow is the source-to-coefficient-lens parametrization. The second is the deck-invariant scalar readout.

Readout quotient

For q(A,B)=(A+B,AB)q(A,B)=(A+B,AB),

det⁡Dq=A−B.\boxed{ \det Dq=A-B. }

On the generic physical mass diagonal y2=y1=y≠0y_2=y_1=y\ne0,

(A,B)=(4y2,0),det⁡Dq=4y2≠0.(A,B)=(4y^2,0), \qquad \det Dq=4y^2\ne0.

Thus the scalar quotient is smooth there. Its loss of the ordered channel label is a finite deck identification, not local rank loss.

Source parametrization

For the composite source readout,

det⁡D(y1,y2)(s,p)=−32y1y2(y12−y22).\boxed{ \det D_{(y_1,y_2)}(s,p) =-32y_1y_2(y_1^2-y_2^2). }

Hence this Jacobian vanishes on both signed mass diagonals y2=±y1y_2=\pm y_1. The source reaches p=0p=0 with quadratic contact:

p=(y1−y2)2(y1+y2)2.p=(y_1-y_2)^2(y_1+y_2)^2.

Meaning

Two phenomena previously grouped as “projection” are now separated:

lens→readout:smooth finite deck quotient,source→lens/readout:ramified physical specialization.\boxed{ \begin{array}{rcl} \text{lens}\to\text{readout} &:&\text{smooth finite deck quotient},\\ \text{source}\to\text{lens/readout} &:&\text{ramified physical specialization}. \end{array} }

The physical channel reduction is encoded by tangency in the source map, whereas the scalar readout forgets only the ordering of the resulting channels. Neither requires a new carrier divisor.

This typing matters cross-sector: a physical locus can be singular for the source parametrization while remaining smooth in coefficient and readout space.

Durable evidence

View source on GitHub