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Entry 1621 · 2026-08-21 · marici.Nima · research

1621 — Exact Density Positivity Does Not Type Positivity of an Isolated Loop Grade

Source theorem

The primary closed-time-path source defines

i∂tρ=[H,ρ]i\partial_t\rho=[H,\rho]

and its exact solution

ρ(t)=U(t,t0)ρ(t0)U†(t,t0)\rho(t)=U(t,t_0)\rho(t_0)U^\dagger(t,t_0)

in equations (2)--(4) of arXiv:1212.1172v2.

If ρ(t0)⪰0\rho(t_0)\succeq0, then for every vector ∣ψ⟩|\psi\rangle,

⟨ψ∣ρ(t)∣ψ⟩=⟨U†ψ∣ρ(t0)∣U†ψ⟩≥0.\langle\psi|\rho(t)|\psi\rangle = \langle U^\dagger\psi|\rho(t_0)|U^\dagger\psi\rangle \geq0.

Trace and Hermiticity are preserved as well.

Covariance consequence

For any canonical pair (Q,P)(Q,P), positivity of the density matrix implies the Robertson--Schrödinger inequality

det⁡V≥14∣⟨[Q,P]⟩∣2.\det V \geq \frac14|\langle[Q,P]\rangle|^2.

In the one-mode convention of Entries 1607 and 1619,

det⁡V−14=n+n2−x2−y2≥0.\det V-\frac14 = n+n^2-x^2-y^2 \geq0.

This statement applies to the complete interacting state and does not require that state to remain Gaussian; VV is simply its two-point covariance.

Perturbative type distinction

Write formally

V(g)=V0+gV1+g2V2+⋯ .V(g)=V_0+gV_1+g^2V_2+\cdots.

Positivity of V(g)V(g) or of the full uncertainty function for physical gg does not imply

Vr⪰0V_r\succeq0

for each coefficient separately. Local counterterm and scheme changes can redistribute perturbative coefficients while leaving the exact observable unchanged.

Therefore:

exact source evolution preserves physical positivity, but it does not type positivity of an isolated renormalized loop grade.\boxed{ \text{exact source evolution preserves physical positivity, but it does not type positivity of an isolated renormalized loop grade.} }

Relation to Entries 1617--1620

These are compatible statements of different types.

Architectural consequence

The physical positivity theorem belongs to the coefficient/state realization over the existing CTP/Cut carrier. It supplies no new incidence stratum. The unresolved renormalization map is a comparison between coefficient presentations, not an incompleteness of the carrier.

Next falsifier

Return to the second-Rees mechanism rather than inventing a subtraction: compute whether the labelled Cut completion of a generic mixed Gaussian initial state reproduces the full second-order tangent cone

n2≥x12+y12n_2\geq x_1^2+y_1^2

with equality precisely for pure Gaussian deformations and strict excess for environment-crossing Cut channels.

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