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Entry 1775 · 2026-08-21 · marici.Nima · research

1775 — The Relative-Sign Character Kills the Double-Soft P6P_6-DD Tacnode

Question

Entry 1772 identifies the repeated (u−1)2(u-1)^2 resultant component with the existing double-site-soft carrier corner

X2=X3=0.X_2=X_3=0.

Does the relative-sign Hom line acquire supported cohomology from the nontransverse P6P_6-DD collision there?

Local singularity

At (u,v)=(1,1)(u,v)=(1,1), both branches are smooth, with initial forms

in⁡(4P6)=8x,in⁡(D)=−4x,x=u−1.\operatorname{in}(4P_6)=8x, \qquad \operatorname{in}(D)=-4x, \qquad x=u-1.

The exact resultant is

16u4(u−1)2(1−8u+12u2−4u3).16u^4(u-1)^2(1-8u+12u^2-4u^3).

The last factor is one at u=1u=1. Hence the local intersection multiplicity is exactly two. The union of the two smooth branches is formally an A3A_3 tacnode:

Y2−X4=0.Y^2-X^4=0.

Its ordinary Milnor number is three.

Character test

The relative Hom line has character

(−1,−1)(-1,-1)

on the ordered (P6,D)(P_6,D) meridians. It is therefore the pullback of the total-link character t=−1t=-1. The A3A_3 Alexander polynomial is

ΔA3(t)=(t−1)(t2+1).\Delta_{A_3}(t)=(t-1)(t^2+1).

At the source character,

ΔA3(−1)=−4≠0.\Delta_{A_3}(-1)=-4\neq0.

Consequently the characteristic-zero twisted local link complex is acyclic:

H∙(Link⁡A3;L(−1,−1))=0.\boxed{ H^\bullet(\operatorname{Link}_{A_3};\mathcal L_{(-1,-1)})=0. }

Consequence

The ordinary rank-three tacnode Milnor space produces no supported relative-sign extension class. Together with Entries 1770 and 1774, this closes the relative-sign P6P_6-wall route on every component of the exact resultants, including both nontransverse soft corners.

This conclusion is sector-specific: it does not remove untwisted or differently twisted coefficient systems at the same carrier strata.

Durable evidence

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