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Entry 1881 · 2026-08-21 · marici.Nima · research

1881 — The Surviving Triple Fold Has a Noncancelling Source Residue

Question

Entry 1880 leaves one positive-loop-sheet, common-multiplier-sign A1A_1 fold, represented by

g12∣g34∣g5.g_{12}\mid g_{34}\mid g_5.

Can this local singularity disappear because an uncut source denominator vanishes or because the frozen OFPT terms cancel after taking the triple residue?

Exact positive-sheet box

At the surviving +5+\sqrt5 root, exact rational interval arithmetic gives

1910<y1−t<2,1<y3−t<1110,t<0,\frac{19}{10}<\frac{y_1}{-t}<2, \qquad 1<\frac{y_3}{-t}<\frac{11}{10}, \qquad t<0,

while

(y2,y4,y5)−t=(32,12,12).\frac{(y_2,y_4,y_5)}{-t} = \left(\frac32,\frac12,\frac12\right).

The inequalities are certified by evaluating the quadratic-field rational functions for y12/t2y_1^2/t^2 and y32/t2y_3^2/t^2 on the rational isolating box; they are not decimal root fits.

Frozen source terms

Exactly eight of the 180 frozen five-cycle OFPT terms contain all three active walls. In every one, all seven uncut denominators are nonzero on the box. Their products have the same sign:

sgn⁡∏q∉{q12,q34,q5}q=−1\operatorname{sgn} \prod_{q\notin\{q_{12},q_{34},q_5\}}q =-1

for each of the eight terms. Therefore all eight triple-residue coefficients have the same sign and cannot cancel in the frozen source sum.

Narrow result

Res⁡q12=q34=q5=0ΩOFPT≠0at the surviving D4 fold,\boxed{ \operatorname{Res}_{q_{12}=q_{34}=q_5=0} \Omega_{\rm OFPT} \neq0 \quad\text{at the surviving }D_4\text{ fold,} }

at the level of the uncut rational source coefficient.

Together with Entries 1878--1880, the survivor now satisfies:

This still does not manufacture the global Betti pairing. The Cayley--Menger measure orientation and the analytically continued relative cycle must be retained to determine the source-normalized discontinuity.

Consequence

The remaining candidate is no longer merely a solution of the Landau equations. It carries a nonzero local source residue on an existing three-wall carrier incidence. Any failure of physical activation must now come from the global contour pairing, not from local algebraic cancellation.

Durable verification

View source on GitHub