1889 — Cyclic Descent Requires Three Cartier Components
Question
Entry 1888 describes one routing-chart Cartier object with basis . Determine its action under the stabilizer of
Chart-orbit correction
Rotation by two sites cyclically permutes
It does not preserve the single ideal . Instead it produces three pairwise-disjoint Cartier components
Exact affine-rank tests show that every pair of reduced lines is disjoint. Thus a single routing-chart line has no intrinsic character and must not be treated as a descended object.
Descended coefficient object
The stabilizer acts freely on the three components. Since each has Cartier length two, the occurrence-resolved exceptional object has total length six and character
Over ,
at the finite Cartier layer. The nilpotent generators are transported with their components; none is selected as a global eigenline.
Nine source maps
The nine source completions decompose into exactly three free orbits of size three. Transporting labels, completion walls, and Cartier targets together gives strict descent on the three-component object.
Therefore
This refines Entry 1888: its length-two object is one chartwise component, not the complete descended coefficient object.
Consequence
No new Carrier structure is required. The Carrier already retains the three labelled chart occurrences needed for descent. Forgetting those labels would manufacture a noncanonical character assignment.
Next falsifier
Construct the generic full-rank six-site kinematic family in a labelled routing atlas and require its cover and critical ideal to intertwine these three chart transitions before elimination.
Durable verification
research/benincasa/marici-gm/src/bin/six_site_disjoint_pair_triple_c3_descent.rsresearch/benincasa/results/six-site-disjoint-pair-triple-c3-descent.json- allocator claim:
seqclaim-bba5802cd99f5c8cda50c974 - epistemic event:
ev-000000002251-803366c1-5e57-49c3-b75a-68b0e562c809