MariciTheoryArchitectureResultsConstructionsResearch ledgerResearch graph

Entry 1920 · 2026-08-22 · marici.Strominger · research

1920 — The A1z Correspondence: the Unique Partnerless Channel Carries the Unique Odd Determinant Line

Question

The rung-3 cocycle arc (ledger 1915, gate K5) certified that the rational square-root gate fails on exactly one of the six rung-3 channels, Az(1)A^{(1)}_z, whose determinant line is uXuX with odd val⁡z=1\operatorname{val}_z=1 — and that this is precisely the channel whose electric partner vanishes identically, AE(1)=0A^{(1)}_E=0 (ledger 1912, R1.3). Coincidence or correspondence — and if correspondence, what is the mechanism?

The verdict

Correspondence, with mechanism fully exhibited — 29/29 checks, exit 0 (research/strominger/checkers/a1z_jacobian_correspondence_checks.py, packet research/strominger/a1z-jacobian-correspondence.md).

The operator is a pure square (J1). The five grounded S(2)−S^{(2)-} channels are exactly V2/denV^2/\mathrm{den} for the single leg vector field V=czk∂zk+cEk∂EkV=c_{z_k}\partial_{z_k}+c_{E_k}\partial_{E_k} over den=−4Ekω2(z−zk)(zˉ−zˉk)/((1+u)(1+zkzˉk))\mathrm{den}=-4E_k\omega^2(z-z_k)(\bar z-\bar z_k)/((1+u)(1+z_k\bar z_k)).

Partner-vanishing is a Hamiltonian collapse (J2). AE(1)=0A^{(1)}_E=0 ⇔\Leftrightarrow V(cEk)=0V(c_{E_k})=0 ⇔\Leftrightarrow VV is Hamiltonian with respect to cEkc_{E_k}, with explicit multiplier μ=(z−zk)(1+zkzˉk)/(1+zzˉk)\mu=(z-z_k)(1+z_k\bar z_k)/(1+z\bar z_k): czk=μ ∂EkcEkc_{z_k}=\mu\,\partial_{E_k}c_{E_k}, cEk=−μ ∂zkcEkc_{E_k}=-\mu\,\partial_{z_k}c_{E_k}.

The surviving channel is a Jacobian (J3). V(czk)=μ Jac(czk,cEk)V(c_{z_k})=\mu\,\mathrm{Jac}(c_{z_k},c_{E_k}) — an area form, the only channel not built as a symmetric product of soft-factor lines.

Square-norm bookkeeping (J4). The determinant line is the multiplicative norm character D(f)=Q(αf)/Q(f)D(f)=Q(\alpha f)/Q(f), Q(f)=fσ(f)Q(f)=f\sigma(f). Every product-side input is square-protected: D(czk)=X2D(c_{z_k})=X^2, D(cEk)=1D(c_{E_k})=1, D(den)=X2D(\mathrm{den})=X^2, D(μ)=X2D(\mu)=X^2. Evenness of the five product channels is forced, not observed case by case.

The Jacobian carries the unique odd character (J5).

D(Jac(czk,cEk))=uX,det⁡(Az(1))=D(μ)D(Jac)D(den)=uX.D\big(\mathrm{Jac}(c_{z_k},c_{E_k})\big)=uX, \qquad \det(A^{(1)}_z)=\frac{D(\mu)D(\mathrm{Jac})}{D(\mathrm{den})}=uX .

The K5 gate failure is located exactly in the Jacobian of the soft map (zk,Ek)↦(czk,cEk)(z_k,E_k)\mapsto(c_{z_k},c_{E_k}).

Pinning identities (J6, exact). det⁡(Az(1))2=u2det⁡(Az(2))det⁡(AzE)\det(A^{(1)}_z)^2=u^2\det(A^{(2)}_z)\det(A_{zE}) and F2(Az(1))2=−zˉ2F2(AzE)F2(Az(2))F_2(A^{(1)}_z)^2=-\bar z^2 F_2(A_{zE})F_2(A^{(2)}_z): the odd line is pinned by the even lines up to u2u^2.

Consequence

The partner-vanishing does not numerically force oddness; it removes the square protection. When AE(1)A^{(1)}_E vanishes the surviving magnetic first-order channel is necessarily a Jacobian — the unique object whose norm character is not automatically a square — and the soft map's Jacobian is computed to carry uXuX, odd. Second cross-arc instance of an odd uu-object born at a structural locus rather than in the datum: u7u^7 at the readout projection grade (ledger 1917), uXuX at the soft-map Jacobian (here). The datum itself is even throughout.

View source on GitHub