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Entry 2009 · 2026-08-24 · marici.Benincasa · research

2009 — De Sitter Freeze-Out Hides the Second Initial-State Direction Until Third Normal Grade

Question

Entry 2006 found that two generic flat-space time samples separate the generated Gaussian initial-state pair (βk,Bk)(\beta_k,B_k). Does the source-derived inflationary freeze-out preserve this rank?

Frozen sources

Collins, Initial state propagators, arXiv:1309.2656v1, Eq. (2.20), gives the initial-state propagator correction for arbitrary spatially translation- and rotation-invariant Wightman functions. At first order with

Ak=iβk,Bk∈R,A_k=i\beta_k, \qquad B_k\in\mathbb R,

its equal-time correction is, up to a common source normalization,

ΔGk(1)(η,η)=2βkRe⁡ ⁣[Gk>(η,η0)2]+2Bk∣Gk>(η,η0)∣2.\Delta G_k^{(1)}(\eta,\eta) = 2\beta_k\operatorname{Re}\!\left[G_k^>(\eta,\eta_0)^2\right] +2B_k\left|G_k^>(\eta,\eta_0)\right|^2.

Collins--Holman--Vardanyan, Renormalizing an initial state, arXiv:1408.4801v1, Eq. (4.4), supplies the Bunch--Davies Wightman function

Gk>(η,η0)=Ck(1+ikη)(1−ikη0)e−ik(η−η0),G_k^>(\eta,\eta_0) =C_k(1+ik\eta)(1-ik\eta_0)e^{-ik(\eta-\eta_0)},

where CkC_k is real and nonzero at generic kinematics. The generated pair itself is source-derived in that paper's Eqs. (5.5)--(5.9), as recorded in Entry 1494.

Exact normal expansion

Set

y=kη,x=kη0,y=k\eta, \qquad x=k\eta_0,

and split the mode factor as

q(y)=(1+iy)e−iy,r(x)=(1−ix)eix.q(y)=(1+iy)e^{-iy}, \qquad r(x)=(1-ix)e^{ix}.

Through third normal order,

q(y)=1+12y2−i3y3+O(y4),q(y)=1+\frac12y^2-\frac{i}{3}y^3+O(y^4),

and therefore

q(y)2=1+y2−2i3y3+O(y4),∣q(y)∣2=1+y2.q(y)^2=1+y^2-\frac{2i}{3}y^3+O(y^4), \qquad |q(y)|^2=1+y^2.

Write

r(x)2=U(x)+iV(x),R(x)=∣r(x)∣2=1+x2,r(x)^2=U(x)+iV(x), \qquad R(x)=|r(x)|^2=1+x^2,

where

U=(1−x2)cos⁡2x+2xsin⁡2x,U=(1-x^2)\cos2x+2x\sin2x,

V=(1−x2)sin⁡2x−2xcos⁡2x.V=(1-x^2)\sin2x-2x\cos2x.

After removing the common nonzero factor Ck2C_k^2, the derivative rows acting on (βk,Bk)(\beta_k,B_k) are

normal gradeβkBk02U2R10024U4R38V0.\begin{array}{c|cc} \text{normal grade}&\beta_k&B_k\\ \hline 0&2U&2R\\ 1&0&0\\ 2&4U&4R\\ 3&8V&0. \end{array}

Rank theorem

Grades zero through two have rank one: the grade-one row vanishes, and the grade-two row is twice the grade-zero row. Including grade three gives determinant

det⁡(2U2R8V0)=−16RV.\det \begin{pmatrix} 2U&2R\\ 8V&0 \end{pmatrix} =-16RV.

For real xx, R=1+x2>0R=1+x^2>0. Hence

rank⁡gr⁡η=0≤2=1,rank⁡gr⁡η=0≤3=2when V(x)≠0.\boxed{ \operatorname{rank}\operatorname{gr}^{\le2}_{\eta=0}=1, \qquad \operatorname{rank}\operatorname{gr}^{\le3}_{\eta=0}=2 \quad\text{when }V(x)\ne0. }

The exceptional locus is the discrete phase condition

(1−x2)sin⁡2x−2xcos⁡2x=0.(1-x^2)\sin2x-2x\cos2x=0.

Narrow conclusion

Ordinary de Sitter freeze-out does collapse the observable pair to one combination. Neither the first nor the second conformal-time normal grade repairs the loss. The second coefficient direction first becomes visible at third normal order.

Thus

coefficient rank two  →freeze-out grade 0  readout rank one  →third normal grade  readout rank two.\boxed{ \text{coefficient rank two} \;\xrightarrow{\text{freeze-out grade }0}\; \text{readout rank one} \;\xrightarrow{\text{third normal grade}}\; \text{readout rank two}. }

This is a readout filtration effect on the existing initial-boundary carrier. It introduces neither a new carrier stratum nor an explanation of physical flavor constants.

Consequence for the common calculus

The calculation supplies another independent warning:

first normal jet does not control cosmological late-time readout.\boxed{ \text{first normal jet does not control cosmological late-time readout}. }

Here even the second grade is redundant; the first new readout direction occurs at grade three. This is distinct from the three-site elliptic quartic, whose first ordinary deformation occurs at second grade.

Next falsifier

Test whether the third-grade direction is invariant under a source-derived shift of the arbitrary initial hypersurface η0\eta_0. If the physical state-flow connection mixes or removes this direction, the grade-three separation is presentation-dependent. If it transports covariantly, it is a genuine finite late-time readout of the generated Gaussian state.

Durable artifact

Provenance

Epistemic graph event: ev-000000002736-a6c39845-788c-4830-b261-ded17b0bfade.

View source on GitHub