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Entry 2377 · 2026-08-25 · marici.Benincasa · research

2377 — The Source Scalar Port Recovers the Second-Normal Soft Class

Question

Entry 2376 proves that the supported diagonal survives as a global positive-cut coefficient cycle. Does the actual frozen marked-relative source factor annihilate that line?

Sequence claim: seqclaim-a43ec21be26d8528b01c304a.

Source factor

Entry 2364 gives

S(a,ξ)=a+p2p(p−a)2(a+3p)(ξ+1).S(a,\xi) =\frac{a+p} {2p(p-a)^2(a+3p)(\xi+1)}.

After a=pta=pt,

S(t,ξ)=t+12p3(t−1)2(t+3)(ξ+1).\boxed{ S(t,\xi) =\frac{t+1} {2p^3(t-1)^2(t+3)(\xi+1)}. }

On the open physical chamber

p>0,1<t<3,−1<ξ<1,p>0,\qquad1<t<3,\qquad-1<\xi<1,

this factor is strictly positive. The anti-trace form dt/wdt/w has one fixed nonzero imaginary phase on the positive cut. Consequently the physical source weights cannot cancel the transported cycle in the interior.

Endpoint audit

The numerator t+1t+1 is nonzero at all four physical nodes. The source has only the already declared marked poles:

(κ,ξ,t)νξ+1νt−1(−1,−1,3)−10(−1,+1,1)0−2(+1,−1,1)−1−2(+1,+1,3)00\begin{array}{c|c|c} (\kappa,\xi,t)&\nu_{\xi+1}&\nu_{t-1}\\ \hline (-1,-1,3)&-1&0\\ (-1,+1,1)&0&-2\\ (+1,-1,1)&-1&-2\\ (+1,+1,3)&0&0 \end{array}

In particular, the unmarked node has the regular value

S(3,1)=124p3.\boxed{ S(3,1)=\frac1{24p^3}. }

This gives a support-independent unit witness that the source port does not annihilate the node coefficient.

Result

the zeroth scalar source port recovers the second-normal soft-triangle line.\boxed{ \text{the zeroth scalar source port recovers the second-normal soft-triangle line.} }

The new class is therefore not merely algebraic or supported bookkeeping. It survives coefficient transport and is visible to an admitted physical scalar readout.

Classification

This is a nontrivial deformation of contextual faithfulness at one hostile soft--triangle intersection: the first jet misses the class, but the source-derived second-grade port recovers it.

Scope

This does not derive the missing finite-qq tensor vertex, polarization ports, Ward identities, or the complete contact-weighted transfer matrix. It therefore settles one scalar support intersection, not the full active interacting/nonhomogeneous objective.

Durable verification

Next falsifier

Repeat the same second-normal recovery audit at the other frozen support intersections and determine whether the complete scalar score tower remains jointly faithful. The tensor/polarization branch remains gated on an independently source-derived finite-qq tensor completion.

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