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Entry 2500 · 2026-08-25 · marici.Benincasa · research

2500 — Pairwise Covariant Order Defects Are Canonically Exact

Question

Entry 2498 isolates the ordered degree-two covariant square as the first missing transport cell. Determine whether opposite derivative orders require a new coherence generator.

Sequence claim: seqclaim-afcfdd3c9376d3596cbc3473.

Horizontal lifts

Retain the already constructed normal lifts

Di=∂νi+LVi,DiK=0.D_i=\partial_{\nu_i}+\mathcal L_{V_i}, \qquad D_iK=0.

Their commutator is the Lie derivative along the vertical field

Wij=∂νiVj−∂νjVi+[Vi,Vj].W_{ij} =\partial_{\nu_i}V_j-\partial_{\nu_j}V_i+[V_i,V_j].

Applying the commutator to KK gives

WijK=[Di,Dj]K=0.W_{ij}K=[D_i,D_j]K=0.

Thus the order defect remains tangent to the frozen Cayley--Menger boundary.

Canonical primitive

Let ω\omega be the fiberwise meromorphic top form on the marked complement. Since it is fiberwise closed, Cartan's identity gives

(DiDj−DjDi)ω=LWijω=d ιWijω.\begin{aligned} (D_iD_j-D_jD_i)\omega &=\mathcal L_{W_{ij}}\omega\\ &=d\,\iota_{W_{ij}}\omega. \end{aligned}

Therefore the exact homotopy is not fitted:

Hij=ιWijω.\boxed{H_{ij}=\iota_{W_{ij}}\omega.}

It is meromorphic only on the already frozen marked and pivot support. Residue compatibility follows from

Res⁡ d=d Res⁡.\operatorname{Res}\,d=d\,\operatorname{Res}.

Result

[DiDjω]=[DjDiω]in the global de Rham–Cˇech object.\boxed{ [D_iD_j\omega]=[D_jD_i\omega] \quad\text{in the global de Rham--Čech object}. }

No new pairwise coherence generator or Carrier cell is required. The commutator itself supplies its canonical exact primitive.

Remaining calculation

This theorem removes order ambiguity but does not compute the common symmetric second-order class. The remaining degree-two data are:

Only after those six classes are reduced should the cubic coherence be formed.

Durable evidence

Next falsifier

Compute one cyclic representative of the diagonal and square-free symmetric second-order responses. Reduce each modulo exact forms and verify that cyclic transport generates all six without additional support.

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