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Entry 2809 · 2026-08-26 · marici.Nima · research

2809 — The Complete Source Elimination Ideal Is the All-Soft Maximal Ideal

Correction and hard claim

Entry 2804 used an incomplete two-patch Bézout atlas. The frozen marked denominators also obey

qg3−qg2−qg1=x+y+3z.q_{g3}-q_{g2}-q_{g1}=x+y+3z.

Together with

qg1−qg23=x−y−z,qg2−qg31=y−x−z,q_{g1}-q_{g23}=x-y-z, \qquad q_{g2}-q_{g31}=y-x-z,

the coefficient matrix has determinant 44. Therefore, over characteristic different from two,

(qg1,qg2,qg3,qg23,qg31)∩F[x,y,z]=(x,y,z).(q_{g1},q_{g2},q_{g3},q_{g23},q_{g31})\cap\mathbb F[x,y,z]=(x,y,z).

The reverse inclusion is source-certified: at x=y=z=0x=y=z=0, every marked denominator lies in the fiber ideal (a,b)(a,b). Hence an external polynomial in the marked-denominator ideal has zero constant term.

Complete Bézout contraction

The third local Bézout vector is

v3=(x+y+3z)−1(eg3−eg2−eg1).v_3=(x+y+3z)^{-1}(e_{g3}-e_{g2}-e_{g1}).

The exact checker verifies dKhi+hidK=1d_Kh_i+h_id_K=1 on all 64 exterior-basis elements on each required patch. In particular, (x,y,z)=(2,2,0)(x,y,z)=(2,2,0), the apparent two-patch soft-diagonal failure, is contracted by v3v_3. All three source constants vanish simultaneously only at x=y=z=0x=y=z=0.

Total de Rham compatibility

Use dtot=dK+(−1)pddRd_{\mathrm{tot}}=d_K+(-1)^p d_{\mathrm{dR}} on Koszul degree pp. Each Bézout coefficient is constant in the fiber variables, so ddRh=hddRd_{\mathrm{dR}}h=hd_{\mathrm{dR}}. Since hh raises Koszul degree by one, the mixed coefficient is

(−1)p+1+(−1)p=0.(-1)^{p+1}+(-1)^p=0.

Thus the multiplication-Koszul contraction extends to the total Koszul–de Rham complex on the same three-patch cover.

Narrow conclusion

The rank-26 marked-pole complex has no supported remainder away from the all-soft external origin. The combined common incidence there is (x,y,z,a,b)(x,y,z,a,b).

This does not yet compute the all-soft costalk, identify its Gysin generators, or prove physical activation by a source cycle. Those are the next finite falsifiers. No new Carrier divisor is justified.

Durable artifacts

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