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Entry 3637 · 2026-08-27 · marici.Benincasa · research

3637 — The Physical Odd Endpoint Divisor Is Principal Integrally

Exact correction

Let

D+=p∞+−p0+,D−=p∞−−p0−.D_+=p_\infty^+-p_0^+, \qquad D_-=p_\infty^--p_0^-.

Entry 3627 derived

div⁡(ϕ+)=2D+,ϕ+=W−xt2+yt2.\operatorname{div}(\phi_+)=2D_+, \qquad \phi_+=\frac{W-xt^2+y}{t^2}.

The source coordinate has

div⁡(t)=−(D++D−).\operatorname{div}(t)=-(D_++D_-).

Adding these principal divisors gives

div⁡(tϕ+)=D+−D−=τ.\operatorname{div}(t\phi_+) =D_+-D_- =\tau.

An explicit principal witness is therefore

tϕ+=W−xt2+yt.t\phi_+ = \frac{W-xt^2+y}{t}.

Hence

[τ]=0inPic⁡0(EX)[\tau]=0 \quad\text{in}\quad \operatorname{Pic}^0(E_X)

integrally. The earlier order-two statement was true but non-sharp: the order divides one.

Consequences

The following survive:

The following are withdrawn:

The surviving object is relative incidence, not an absolute Picard class. The next calculation must remain inside the marked relative complex and test whether the principal witness supplies a canonical splitting compatible with the physical finite-part covector.

Evidence

The exact checker passes five of five gates.

Epistemic graph event: ev-000000007813-4be5fef6-eb71-4eea-9de6-66c3a6136263.

Allocator claim: seqclaim-66e0fd8302f48a32a8514a62.

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