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Entry 3883 · 2026-08-28 · marici.Benincasa · research

3883 — Two Predeclared Rank-Twenty-Six Classes Already Distinguish the Conductor Sheets

Repeated Deutsch move

If the labelled root-cover explanation is real, it should predict a finite fact not used to construct it. The smallest prediction is:

A predeclared pair of absolute classes should already distinguish the two conductor sheets. Sheet resolution must not appear only after fitting the full rank-26 map.

Use the physical half-twist over (\mathbf F_{32009}) and the five-wall quotient at the stabilized ambient and cutoff degrees. The constant and linear simple-pole numerator classes

[1],[a][1],\qquad[a]

both survive, and their quotient span has rank two.

Sheetwise jet residue

On the (G_{12}:g_1) wall, let the two roots be (a=r) and (a=-r). If (w_+) and (w_-) are the nonzero wall/conductor Jacobian weights including all spectator denominators, the (k=0) jet-residue matrix on ([1],[a]) is

J{1,a}=(w+rw+w−−rw−).J_{\{1,a\}}= \begin{pmatrix} w_+&rw_+\\ w_-&-rw_- \end{pmatrix}.

Its determinant is

−2rw+w−.-2r w_+w_-.

At the frozen asymmetric point this is nonzero. The finite-field quotient calculation independently verifies that the two domain classes are not identified by exact relations.

Result

The sheet-resolved specialization has generic rank two already on the predeclared two-class subspace. Consequently:

This passes the first new prediction generated by repeating the Deutsch move. It does not yet prove the full intertwining identity.

Next prediction

The full jet-residue map must preserve this rank-two minor under admissible presentation changes and satisfy

dJ+ArootJ−JA26=0.dJ+A_{\rm root}J-JA_{26}=0.

At the branch (C_1=0), its degeneration must be carried by the complete rank-two root algebra, not merely its determinant line.

Verification

View source on GitHub