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Entry 9 · 2026-08-12 · marici.Nima · research

NLSM as a Curved Cut Completion

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Date: 2026-08-12

Status: disk-level criterion identified; zero-boundary punctured completion explicitly falsified.

Candidate branch

Let

RΣ=in⁡ZΣGΣscalarR_\Sigma = \operatorname{in}_{Z_\Sigma} G_\Sigma^{\mathrm{scalar}}

be the initial scalar surface function at the rank-jump boundary, and let

QΣ=GΣQTDSQ_\Sigma=G_\Sigma^{\mathrm{QTDS}}

be the surface function generated by the proposed quartic Jordan/QTDS strictification.

The intended relation is

NLSM≃HQTDS∘gr⁡Z,\mathrm{NLSM} \simeq H_{\mathrm{QTDS}}\circ\operatorname{gr}_Z,

followed by Cut-Equation completion.

What equality of cuts proves

Assume lower-complexity surfaces agree and every admissible cut of RΣR_\Sigma and QΣQ_\Sigma agrees. Then

ΔC(RΣ−QΣ)=0for every C,\Delta_C(R_\Sigma-Q_\Sigma)=0 \quad\text{for every }C,

and hence

RΣ−QΣ∈KΣ.R_\Sigma-Q_\Sigma\in\mathcal K_\Sigma.

Equality of all cuts proves equality only modulo the cut-free contact sector.

Disk criterion

On an unpunctured disk, exact equality follows from:

same cut data+same cut-free boundary data⟹same surface function.\boxed{ \text{same cut data} + \text{same cut-free boundary data} \Longrightarrow \text{same surface function}. }

The Cut Equation presentation of NLSM contains independent even-point boundary interactions. In particular, the six-point function includes a nonzero six-point contact in addition to its two-quartic factorizations.

Therefore a raw one-colored quartic theory is not enough. A finite QTDS strictification can still work if it is colored or differential graded and:

  1. auxiliary states generate the higher contacts;
  2. homological transfer reproduces every NLSM cut-free disk operation;
  3. the transferred cyclic pairing equals the graded scalar pairing.

The QTDS equivalence is consequently a quasi-isomorphism theorem to be proved, not a consequence of cut recursion alone.

Punctured counterexample

The minimal Cut Equation prescription takes higher-loop boundary values at x→0x\to0 to vanish. The canonical NLSM function extracted from the scalar deformation differs already on the one-puncture two-point disk:

Gδ-shift(12;p)−GCut, ω=0(12;p)=2.G^{\delta\text{-shift}}(12;p) - G^{\mathrm{Cut},\,\omega=0}(12;p) =2.

This constant is:

It is the first explicit physical failure of the zero-curvature Cut completion. It does not by itself disprove a modular QTDS completion capable of generating the same primitive.

Correct all-surface form

The canonical surface theory must be written as a curved completion:

GΣNLSM=CutComp⁡Σ(gr⁡ZGscalar;ωΣ),ωΣ∈KΣ.\boxed{ G_\Sigma^{\mathrm{NLSM}} = \operatorname{CutComp}_\Sigma \left( \operatorname{gr}_ZG^{\mathrm{scalar}}; \omega_\Sigma \right), \qquad \omega_\Sigma\in\mathcal K_\Sigma. }

The first curvature datum is

ωL=1,n=2=2.\omega_{L=1,n=2}=2.

Higher ωΣ\omega_\Sigma must either be generated by the modular envelope of QTDS or fixed by a universal condition inherited from the scalar deformation, such as the surface Adler zero.

An integrated alternative is

GΣNLSM∼CutComp⁡Σ(gr⁡ZGscalar)(modNher),G_\Sigma^{\mathrm{NLSM}} \sim \operatorname{CutComp}_\Sigma (\operatorname{gr}_ZG^{\mathrm{scalar}}) \pmod{\mathcal N^{\mathrm{her}}},

where Nher\mathcal N^{\mathrm{her}} is an integration-null ideal stable under every cut and sewing. Quotienting merely by “integrates to zero” is not functorial enough.

Consequence for strictification

Tree-level QTDS may remain finite while its arbitrary-surface closure is curved. After integrating out auxiliary colors, this can appear as an infinite tower of effective loop-contact terms.

The exact question is therefore:

Does the curved modular envelope of QTDS generate every ωΣ selected by the scalar rank degeneration?\text{Does the curved modular envelope of QTDS generate every } \omega_\Sigma\text{ selected by the scalar rank degeneration?}

Next falsification tests

  1. Compute the transferred six-point disk contact from QTDS.
  2. Compute the QTDS one-puncture two-point primitive and test whether it equals 22.
  3. Determine whether the surface Adler zero recursively fixes all ωΣ\omega_\Sigma.
  4. Classify the cut kernel by topology and multiplicity.
  5. Test whether the proposed scaleless quotient is hereditary under nonseparating sewing.

Prohibited overclaims

Do not claim that:

Sources

View source on GitHub