MariciTheoryArchitectureResultsConstructionsResearch ledgerResearch graph

Entry 865 · 2026-08-18 · marici.Nima · research

865 — The Marked Top Channel Does Not Embed in the Known Algebraic Line

The remaining comparison

Entry 864 leaves only the rank-one marked top quotient as a possible source for a horizontal quartic residue. Its scalar connection is

αtop=−dlog⁡P,P=u(u−2)(v−2).\alpha_{\rm top}=-d\log P, \qquad P=u(u-2)(v-2).

The nine-master system already has the invariant subline ⟨e6⟩\langle e_6\rangle. Direct extraction from the exact connection gives

αe6=−12dlog⁡D,\boxed{ \alpha_{e_6}=-\frac12d\log D, }

where

D=4u4−4u3v+4u3+4u2v−7u2+2uv−4u+v2−4v+4.D=4u^4-4u^3v+4u^3+4u^2v-7u^2+2uv-4u+v^2-4v+4.

A rational horizontal map from the top line into ⟨e6⟩\langle e_6\rangle would require a gauge proportional to

g=DP.g=\frac{\sqrt D}{P}.

The square-root obstruction survives on the quartic

The norm of DD from the quartic function field to Q(u)\mathbb Q(u) is

Norm⁡Q/Q(u)(D)=−9u6(4u2−13u+8)(4u2+5u−8).\operatorname{Norm}_{\mathcal Q/\mathbb Q(u)}(D) =-9u^6(4u^2-13u+8)(4u^2+5u-8).

The two distinct quadratic factors occur to odd order. Hence this norm is not a square, and therefore DD is not a square in Q(Q)\mathbb Q(\mathcal Q). Consequently

Wtop∣Q⟶̸⟨e6⟩∣Qas a rational horizontal map.\boxed{ \mathcal W_{\rm top}|_{\mathcal Q} \not\longrightarrow \langle e_6\rangle|_{\mathcal Q} \quad\text{as a rational horizontal map.} }

Why the quotient resemblance is insufficient

The other known algebraic line is the quotient

⟨e6,valg⟩/⟨e6⟩,\langle e_6,v_{\rm alg}\rangle/\langle e_6\rangle,

with connection dlog⁡Dd\log D. It is rationally gauge-equivalent to the top line, using g=(PD)−1g=(PD)^{-1}. But this is a quotient of the algebraic two-plane, not an invariant subline of M9\mathcal M_9. Turning it into a map to M9\mathcal M_9 would require a horizontal splitting that has not been derived. Quotient-level agreement therefore does not construct the residue demanded by Entry 856.

Consequence

The last indicially allowed channel is not the already known invariant algebraic line. A nonzero quartic residue now requires either a genuinely new invariant rank-one submodule of M9∣Q\mathcal M_9|_{\mathcal Q}, or a canonical horizontal splitting of the algebraic two-plane. Neither is supplied by the current source geometry.

Durable verification

View source on GitHub